Answer :

Let AB be the tower and CB its shadow when the angle of elevation of the sun is 30⁰.

∠ACB = 30⁰

∠B = 90⁰

CB = 27 m

DB is the shadow of the tower when the angle of elevation of the sun is 60⁰.

In ∆ACB,

In ∆ADB,

The length of the shadow of the tower is 9 m.

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