A tree breaks due

Suppose AC is the tree broken at point B such that the broken part CB takes the position BD and touches the ground at D.

AD = 30 m

∠ADB = 30⁰

In ∆DAB,

AB = 10√3

Now,

BD = 20√3

So, height of the tree AC,

= AB + BC

= AB + BD

= 10√3 + 20√3

= 30√3

= 30 × 1.73

= 51.9 m

The height of the tree is 51.9 m.