Answer :

Let AB be the tower with height of tower AB = h

At C the angle of depression of car measures 30 and 12 minutes later it reaches D where angle of depression is 45.

Let CD = x, D = y

Here, AB = h, ACB = XAC = 30⁰

ADB = XAD = 45⁰

In ∆ACB,

x + y = √3h ……(1)

In ∆ABD,

H = y ………(2)

From equation 1 and 2,

x + y = √3y

x = (√3 – 1)y

The distance covered by car in 12 minutes is CD = x

So, time taken to cover distance x is 12 minutes.

So, y = Time taken to cover distance DB

= 6 × 2.73

= 16.38 minutes

The time taken by car to reach the tower is 16.38 minutes.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses

A pole stands verGujarat Board Mathematics

As observed from Gujarat Board Mathematics

A string of a kitGujarat Board Mathematics

A circus artist iGujarat Board Mathematics

The angles of eleGujarat Board Mathematics

As observed from Gujarat Board Mathematics

Watching from a wGujarat Board Mathematics

From a point at tGujarat Board Mathematics

From the top of aGujarat Board Mathematics

The shadow of a tGujarat Board Mathematics