Answer :

False

If p and q are in inverse proportion, then


xy = k(constant)


e.g. Let p = 3 and q = 4


Then, pq = 3×4 = 12


Now, p + 2 = 3 + 2 = 5 and q-2 = 4-2 = 2


(p + 2) (q-2) = 5×2 = 10 [not in inverse proportion]


Hence, (p + 2) and (q-2) cannot be in inverse proportion.


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