Q. 74.4( 8 Votes )

There are 200 individuals with a skin disorder, 120 had been exposed to the chemical C1, 50 to chemical C2, and 30 to both the chemicals C1 and C2. Find the number of individuals exposed to

(i) Chemical C1 but not chemical C2

(ii) Chemical C2 but not chemical C1

(iii) Chemical C1 or chemical C2

Answer :

Given:


Total number of individuals with skin disorder = 200


Individuals exposed to chemical C1 = 120


Individuals exposed to chemical C2 = 50


Individuals exposed to chemicals C1 and C2 both = 30


To Find:


(i) Individuals exposed to Chemical C1 but not C2


Let us consider,


Total number of individuals with skin disorder = n(C) = 200


Individuals exposed to chemical C1 = n(C1) = 120


Individuals exposed to chemical C2 = n(C2) = 50


Individuals exposed to chemicals C1 and C2 both = n(C1 C2) = 30


Individuals exposed to Chemical C1 but not C2 = n(C1 - C2)


Venn diagram:



Now,


n(C1 - C2) = n(C1) – n(C1 C2)


= 120 – 30


= 90


Therefore, number of individuals exposed to chemical C � �1 but not C2 = 90


(ii) Individuals exposed to Chemical C2 but not C1


Let us consider number of Individuals exposed to Chemical C2 but not C1 = n(C2 – C1)


Now,


n(C2 – C1) = n(C2) – n(C1 C2)


= 50 – 30


= 20


Therefore, number of individuals exposed to chemical C � �2 but not C1 = 20


(iii) Individuals exposed to Chemical C1 or chemical C2


Let us consider number of Individuals exposed to Chemical C1 or chemical C2 = n(C1 C2)


Now,


n(C1 C2) = n(C1) + n(C2) - n(C1 C2)


= 120 + 50 – 30


= 140


Therefore, number of individuals exposed to chemical C � �1 or C2 = 140


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If and x < 8}, and B = , find :

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RS Aggarwal - Mathematics