If A = {a, b, c,

(i) B - C represents all elements in B that are not in C

B - C = {a, c}

A(B - C) = {a, c}

AB = {a, c, e}

AC = {b, e}

(AB) - (AC) = {a, c}

A(B - C) = (AB) - (AC)

Hence proved

(ii) BC = {e, g}

A - (BC) = {a, b, c, d}

(A - B) = {b, d}

(A - C) = {a, c, d}

(A - B) (A - C) = {a, b, c, d}

A - (BC) = (A - B) (A - C)

Hence proved