Q. 134.6( 5 Votes )

Is it possible to

Answer :

No, HCF does not divided LCM exactly

Using Euclid’s division lemma -


Take a = 520 and b = 25.


a = bq + r. where q is the quotient, r is the remainder and b is the divisor.


If HCF divides LCM completely, r = 0.


Here 520 = 25(20) + 20


So, r = 20


r is not equal to zero


HCF does not divides LCM completely.


So this is not possible for two numbers to have HCF = 25 and LCM = 520.


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