No, ∵ HCF does not divided LCM exactly
Using Euclid’s division lemma -
Take a = 520 and b = 25.
a = bq + r. where q is the quotient, r is the remainder and b is the divisor.
If HCF divides LCM completely, r = 0.
Here 520 = 25(20) + 20
So, r = 20
∵ r is not equal to zero
∴ HCF does not divides LCM completely.
So this is not possible for two numbers to have HCF = 25 and LCM = 520.
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