Q. 2 I5.0( 1 Vote )

# Frame and solve the equations for the following statements:Mary is 3 times older than Nandhini. After 10 years the sum of their ages will be 80. Find their present ages.

At present,

Let age of Nandini = x

Then age of Mary = 3x

After 10 years,

Age of Nandini = x + 10

Age of Mary = 3x + 10

Then according to the question,

[x + 10] + [3x + 10] = 80

x + 10 + 3x + 10 = 80

4x + 20 = 80

4x = 80 – 20

4x = 60

x = 15

3x = 3 × 15 = 45

Hence, Present age of Nandini = 15 years

Present age of Mary = 45 years

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