Q. 55.0( 2 Votes )

If one of the factors of x2 – 6x – 16 is (x + 2) then other factor is
A. x + 5

B. x – 5

C. x + 8

D. x – 8

Answer :

Let the other factor be (x + p)


Then, x2 – 6x – 16 = (x + p)(x + 2)


= x2 + (p + 2)x + 2p


On comparing the coefficients on both sides, we get,


p + 2 = – 6


p = – 8


The other factor is (x – 8).

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