Q. 4 D

# Express the following as a sum of consecutive odd numbers starting with 1112

We know that any square can be expressed as the sum of consecutive odd numbers starting from 1.

n2 = 1 + 3 + 5 + … + (2n-1)

Therefore, 112 = 1 + 3 + 5 + … + (2 × 11-1)

= 1 + 3 + 5 + … + 21

= 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 + 21

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Quiz | Become a Master in Rationalisation46 mins
Quiz | Imp. Qs. on Playing With Numbers45 mins
Mathematics in Real Life34 mins
Real meaning of Geography42 mins
Champ Quiz | Number Series28 mins
On the Number line44 mins
Lets Explore the Number Line - Rational Numbers43 mins
Cell - Number, Size and Shape40 mins
The Number Story.41 mins
Quiz | Imp. Qs. on Rational Numbers42 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses