Q. 4 D

Express the following as a sum of consecutive odd numbers starting with 1

112

Answer :

We know that any square can be expressed as the sum of consecutive odd numbers starting from 1.


n2 = 1 + 3 + 5 + … + (2n-1)


Therefore, 112 = 1 + 3 + 5 + … + (2 × 11-1)


= 1 + 3 + 5 + … + 21


= 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 + 21


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