Step 1: Draw a line segment AB of 9.3 unit. Then, extend it to C so that BC = 1 unit.
Step 2: Now, AC = 10.3 units. Find the center of AC and mark it as O
Step 3: Draw a semi-circle with radius OC and center O.
Step 4: Draw a perpendicular line BD to AC at point B intersecting the semi-circle at D. And then, join OD
Step 5: Now, OBD is a right angled triangle
Here, OD (Radius of semi-circle)
BC = 1
Then, OB = OC – BC
Using Pythagoras theorem,
OD2 = BD2 + OB2
()2 = BD2 + ()2
BD2 = ()2 - ()2
BD2 = ( – ) ( + )
BD2 = 9.3
Thus, the length of BD is
Step 6: Taking BD as radius and B as the center, construct an arc which touches the line segment.
Now, the point where it touches the line segment is at a distance of from O as shown in the figure below
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