Q. 45.0( 3 Votes )

# Factorization of x^{2} + 2x – 8 is

A. (x + 4)(x – 2)

B. (x – 4)(x + 2)

C. (x + 4)(x + 2)

D. (x – 4)(x – 2)

Answer :

Suppose (x + p)(x + q) are two factors of x^{2} + 2x – 8.

Then, x^{2} + 2x – 8 = (x + p)(x + q)

= x^{2} + (p + q)x + pq

So, to factorize we have to find p and q, such that pq = – 8 and p + q = 2.

∴ x^{2} + 2x – 8 = (x + 4)(x – 2)

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