Q. 3 I5.0( 1 Vote )

Factorize:

2m3 + 3m – 2m2 – 3

Answer :

Given 2m3 + 3m – 2m2 – 3=(m × 2m2 + m × 3 + ( – 1) × 2m2 + ( – 1) × 3)


Taking m common from 1st and 2nd term and ( – 1) from 3rd and 4th,


2m3 + 3m – 2m2 – 3= m (2m2 + 3) + ( – 1)(2m2 + 3)


2m3 + 3m – 2m2 – 3= (2m2 + 3)(m – 1)


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