Q. 3 H5.0( 1 Vote )

Factorize:

mx – my – nx + ny

Answer :

Given mx – my – nx + ny =(m × x – m × y + ( – n) × x + n × y)


Taking m common from 1st and 2nd term and ( – n) from 3rd and 4th,


mx – my – nx + ny = m (x – y) + ( – n)(x – y)


mx – my – nx + ny = (m – n)(x – y)


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