Q. 3 G5.0( 1 Vote )

Factorize:

ax3 – bx2 + ax – b

Answer :

Given ax3 – bx2 + ax – b = (x2 × ax – x2 × b + ax – b)


Taking x2 common from 1st and 2nd term and 1 from 3rd and 4th,


ax3 – bx2 + ax – b = (x2 × ax – x2 × b + ax – b)


ax3 – bx2 + ax – b = x2 (ax – b) + (ax – b)


ax3 – bx2 + ax – b = (x2 + 1)(ax – b)


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