Q. 3 F5.0( 1 Vote )

# Factorize:

a^{2}x + abx + ac + aby + b^{2}y + bc

Answer :

Given a^{2}x + abx + ac + aby + b^{2}y + bc = (ax × a + ax × b + by × a + by × b + c × a + c × b)

Taking ax common from 1^{st} and 2^{nd} term and by from 3^{rd} and 4^{th} and c from 5^{th} and 6^{th},

a^{2}x + abx + ac + aby + b^{2}y + bc = ax (a + b) + by (a + b) + c (a + b)

⇒ a^{2}x + abx + ac + aby + b^{2}y + bc = (ax + by + c) (a + b)

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