Q. 3 F5.0( 1 Vote )

# Factorize:</p

Answer :

Given a2x + abx + ac + aby + b2y + bc = (ax × a + ax × b + by × a + by × b + c × a + c × b)

Taking ax common from 1st and 2nd term and by from 3rd and 4th and c from 5th and 6th,

a2x + abx + ac + aby + b2y + bc = ax (a + b) + by (a + b) + c (a + b)

a2x + abx + ac + aby + b2y + bc = (ax + by + c) (a + b)

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