# Find a rational number and also irrational number lying between the numbers 0.3030030003…..and 0.3010010001….

Let a = 0.3010010001….

And, b = 0.3030030003…..

We observe that the second decimal place a has digit 1 and b has digit 3, therefore, a < b. In the third decimal place a has digit 1. So, if we consider rational and irrational numbers

x = 0.302

y = 0.302002000200002…

We find that,

a < x < b

And, a < y < b

Hence, x and y are required rational and irrational numbers respectively.

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