Q. 73.8( 29 Votes )

# Consider f : R <s

It is given that f : R R given by f (x) = 4x + 3

Let f(x) = f(y)

4x +3 = 4y +3

4x = 4y

x = y

f is one- one function.

Now, for y ϵ R, Let y = 4x +3 for any y ϵ R, there exists x = ϵ R

such that, f(x) = F is onto function.

Since, f is one –one and onto

f-1 exists.

Let us define g: R R by g(x) = Now, (gof)(x) = g(f(x)) = g(4x + 3) = (fog)(y) = f(g(xy)) = Therefore, gof = fog = IR

Therefore, f is invertible and the inverse of f is given by

f-1 (y) = g(y) = .

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