Answer :

Using the result n(B) + n(B’) = n(U)


n(B) + 20 = 38


n(B) = 38 – 20 = 18


We have, n(A B) = n(A) + n(B) – n(A B)


n(A B) = 16 + 18 – 12


n(A B) = 34 – 12 = 22


Hence, n(A B) = 22.


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