Answer :

It is given that h: {2, 3, 4, 5} {7, 9, 11, 13} with

h = {(2, 7), (3, 9), (4, 11), (5, 13)}


We can see that all distinct elements of the set (2, 3, 4, 5) have distinct images under h.


h is one–one.


Also, h is onto since for every element of the set {7, 9, 11, 13},


there exists an element x in the set {2, 3, 4, 5} such that h(x) = y.


Therefore, h is a one–one and onto function.


Therefore, h has an inverse.

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