Answer :

⇒ 23 and 2^{2} 5^{7} 7^{5} are co-prime.

Now, we have to write the denominator 2^{2} 5^{7} 7^{5} in the form of 2^{n}5^{m} where, n and m are the non-negative numbers.

2^{3} 5^{2}

2^{2}×5⁷×7⁵

∴ denominator is not of the form 2^{n}5^{m} where, n = 2 and m = 7. Due to one more factor it is not in the form

Thus, is Non-terminating decimal.

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