Q. 135.0( 1 Vote )
In a school 150 students passed X standard Examination. 95 students applied for Group I and 82 students applied for Group II in the Higher Secondary course. If 20 students applied neither of the two, how many students applied for both groups?
Answer :
Given
total no student passed in X standard exam n(U) = 150
No of Students applied for Group I only n(A) = 95
No of Student applied for Group II only n(B) = 82
No of student applied for neither of the exam n(A∪B)' = 20
So No of student applied for exam n(A∪B) = n(U) – n(A∪B)'
= 150 – 20
= 130
From the above Venn diagram
(95–x) + x + (82–x) = 130
No of student applied for both the group x = (95 + 82) – 130
= 177 – 130
= 47
Number of students applied for both the group = 47.
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