Q. 124.6( 35 Votes )

On a morning walk

Answer :

We have to find LCM of 40, 42 and 45 to get the required minimum distance.


For this we find prime factorisations,


40 = 2 × 2 × 2 × 5


42 = 2 × 3 × 7


45 = 3 × 3 × 5


LCM (40, 42, 45) = 2 × 3 × 5 × 2 × 2 × 3 × 7 = 2520


Hence, Minimum distance each should walk 2520 cm. So that each can cover the same distance in complete steps.

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