Answer :

We have to find LCM of 40, 42 and 45 to get the required minimum distance.

For this we find prime factorisations,

40 = 2 × 2 × 2 × 5

42 = 2 × 3 × 7

45 = 3 × 3 × 5

LCM (40, 42, 45) = 2 × 3 × 5 × 2 × 2 × 3 × 7 = 2520

Hence, Minimum distance each should walk 2520 cm. So that each can cover the same distance in complete steps.

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