Q. 8 F5.0( 1 Vote )

Find the LCM and HCF of the following pair of integers and verify that LCM X HCF = Product of two numbers :

902 and 1517

Answer :

Given numbers are 902 and 1517


The prime factorization of 902 and 1517 gives:


902 = 2 × 11 × 41 and 1517 = 37 × 41


Therefore, the H.C.F of these two integers = 41


Now, the L.C.M of 902 and 1517 = 2 ×


11 × 37 × 41 = 33374


Now, we have to verify



L.H.S = L.C.M × H.C.F = 33374 × 41 = 1368334


R.H.S = Product of two numbers = 902 × 1517 = 1368334


Hence, L.H.S = R.H.S


So, the product of two numbers is equal to the product of their HCF and LCM.


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