Q. 8 F5.0( 1 Vote )

# Find the LCM and HCF of the following pair of integers and verify that LCM X HCF = Product of two numbers :902 and 1517

Given numbers are 902 and 1517

The prime factorization of 902 and 1517 gives:

902 = 2 × 11 × 41 and 1517 = 37 × 41

Therefore, the H.C.F of these two integers = 41

Now, the L.C.M of 902 and 1517 = 2 ×

11 × 37 × 41 = 33374

Now, we have to verify L.H.S = L.C.M × H.C.F = 33374 × 41 = 1368334

R.H.S = Product of two numbers = 902 × 1517 = 1368334

Hence, L.H.S = R.H.S

So, the product of two numbers is equal to the product of their HCF and LCM.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos  Interactive Quiz:Euclid's Division Lemma44 mins  Fundamental Theorem of Arithmetic-238 mins  Champ Quiz | Fundamental Principle Of Arithmetic41 mins  Fundamental Theorem of Arithmetic- 143 mins  Euclids Division Lemma49 mins  Quiz | Imp Qs on Real Numbers37 mins  NCERT | Imp. Qs. on Rational and Irrational Numbers44 mins  Application of Euclids Division Lemma50 mins  Relation Between LCM , HCF and Numbers46 mins  Quiz | Fun with Fundamental Theorem of Arithmetic51 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses 