Q. 8 B5.0( 1 Vote )

Find the LCM and HCF of the following pair of integers and verify that LCM X HCF = Product of two numbers :

852 and 1491

Answer :

Given numbers are 852 and 1491


The prime factorization of 852 and 1491 gives:


852 = 2 × 2 × 3 × 71 and 1491 = 3 × 7 × 71


Therefore, the H.C.F of these two integers = 3 × 71 = 213


Now, the L.C.M of 96 and 404 = 2 × 2 × 3 × 7 × 71 = 5964


Now, we have to verify



L.H.S = L.C.M × H.C.F = 5964 × 213 = 1270332


R.H.S = Product of two numbers = 852 × 1491 = 1270332


Hence, L.H.S = R.H.S


So, the product of two numbers is equal to the product of their HCF and LCM.


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