Answer :
Given numbers are 26 and 91.
The prime factorization of 26 and 91 gives:
Here, 131 is the smallest power of the common factor 13.
Therefore, the H.C.F of these two integers = 13
21 × 71 × 131 are the greatest powers of the prime factors 2, 7 and 13 respectively involved in the given numbers.
Now, L.C.M of 6 and 21 is 2 × 7 × 13 = 182
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