# Find the product :(i) (a3) × (2a5) × (4a15)(ii) (5 – 2x) (4 + x)(iii) (x + 3y) (3x – y)(iv) (3x + 2) (4x – 3)(v) (i) (2× 4) (a3 × a5 × a15)

8 a3 + 5 + 15

8 a23 ( an + m = an × am)

ii. 5 × (4 + x) -2x × (4 + x)

(5× 4 + 5x) – (2x × 4 + 2x × x)

(20 + 5x) – (8x + 2x1 + 1 ) ( an + m = an × am)

(20 + 5x) – (8x + 2x2 )

20 + 5x – 8x - 2x2

-2x2 -3x + 20

iii. x × (3x -y) + 3y × (3x -y)

(x × 3x + x × (-y)) + (3y × 3x + 3y × (-y))

(3x1 + 1 - xy) + ((3× 3)xy – 3y1 + 1 ) ( an + m = an × am)

(3x2 - xy ) + (9xy – 3y2 )

3x2 - xy + 9xy - 3y2

3x2 + 8xy - 3y2

iv. 3x × (4x-3) + 2 × (4x-3)

(3x × 4x + 3x × (-3)) + (2× 4x + 2 × (-3))

((3× 4)x1 + 1 -9x) + (8x -6) ( an + m = an × am)

12x2 -9x + 8x -6

12x2 -x -6

v. ( )x( abX = x( )

= Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos  Champ Quiz | Linear Equation in One Variable44 mins  Discussion on Algebric Identities48 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses 