Answer :
= xy – xz + ay – az
Taking x common in xy – xz
we get,
= x(y – z) + ay – az
Taking ‘a’ common in ay – az
we get,
= x(y – z) + a(y – z)
Taking (y – z) common in both the terms
we get,
= (y – z)(x + a)
xy – xz + ay – az = (y – z)(x + a)
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