Answer :
Given : Two brands of chocolates are available in packs of 24 and 15 respectively.
To find : the least number of boxes of each kind.
Solution:
Prime factors of 24 = 2 × 2 × 2 × 3
Prime factors of 15 = 3 × 5
Therefore LCM of 24 and 15 is: 2 × 2 × 2 × 3 × 5 = 120
Number of boxes for first chocolate kind = = 5
Number of boxes for second chocolate kind = = 8
Hence 5 boxes of first kind and 8 boxes of second kind needed to buy.
Rate this question :
How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
view all courses
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation


RELATED QUESTIONS :
Find the LCM and
KC Sinha - MathematicsFind the LCM and
KC Sinha - MathematicsFind LCM and HCF
KC Sinha - MathematicsFind LCM and HCF
KC Sinha - MathematicsFind the LCM and
KC Sinha - MathematicsFind the LCM and
KC Sinha - Mathematics