Q. 145.0( 2 Votes )

# Use the Venn diag

i. From the Venn diagram we get,

U = {1, 2, 3, 4, 5, 6, 8, 9, 10}

G = {1, 2, 4, 8}

H = {2, 6, 8, 10}

ii. U = {1, 2, 3, 4, 5, 6, 8, 9, 10}

G = {1, 2, 4, 8}

H = {2, 6, 8, 10}

G’ = {3, 5, 6, 9, 10} [elements that are present in U but not in G]

H’ = {1, 3, 4, 5, 9} [elements that are present in U but not in H]

G’ H’ = {3, 5, 9} [elements that are present in both G’ and H’]

G H = {1, 2, 4, 6, 8, 10} [elements that are present either in G or in H]

(G H)’ = {3, 5, 9} [elements present in U but not in (G H)]

n(G H)’ = 3 [no. of elements in (G H)’]

G H = {2, 8} [elements present in both G and H]

(G H)’ = {1, 3, 4, 5, 6, 9, 10} [elements present in U but not in (G H)]

n(G H)’ = 7 [no. of elements in (G H)’]

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