Answer :

i. A = {3, 6, 9, 12, 15, 18}

B = {4, 8, 12, 16, 20}

∴ A – B = {3, 6, 9, 15, 18} [elements that are present in A but not in B]

ii. B = {4, 8, 12, 16, 20}

C = {2, 4, 6, 8, 10, 12}

∴ B – C = {16, 20} [elements that are present in B but not in C]

iii. C = {2, 4, 6, 8, 10, 12}

D = {5, 10, 15, 20, 25}

∴ C – D = {2, 4, 6, 8, 12} [elements that are present in C but not in D]

iv. D = {5, 10, 15, 20, 25}

A = {3, 6, 9, 12, 15, 18}

∴ D – A = {5, 10, 20, 25} [elements that are present in D but not in A]

v. A = {3, 6, 9, 12, 15, 18}

C = {2, 4, 6, 8, 10, 12}

∴ A – C = {3, 9, 15, 18} [elements that are present in A but not in C]

∴ n(A – C) = 4 [no. of elements in (A – C)]

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