# Show that the fun

It is given that f : R* R* defined by

check for one-one:

For a function to be one-one, if f(x) = f(y) then x = y.

f(x) = f(y)

x = y

⇒Therefore,  f is one one.

We can see that y ϵ R, there exists , such that

f is onto.

Therefore, function f is one-one and onto.

Now, Let us consider g: N R* defined by

Then, we get,

g(x1) = g(x2)

x1 = x2

g is oneone.

It can be observed that g is not onto as for 1.2 ϵ R there does not exist any x in N such that

Therefore, function g is one –one but not onto.

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