Q. 85.0( 2 Votes )

# If x – y = – 6 an

The identity used here is

(a + b)3 = a3 + 3a2b + 3ab2 + b3

(x – y)3 = x3 + 3x2(– y) + 3x(– y)2 + (– y)3

x3 – 3x2y + 3xy2 – y3

(x – y)3 = x3 – 3x2y + 3xy2 – y3

(– 6)3 = x3 – y3 + 3xy(– x + y)

– 216 + 3 × 4 (– 6) = x3 – y3

– 216 – 72 = x3 – y3

– 288 = x3 – y3

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