Using algebraic i

(5x + 2)(1 – 5x)(5x + 3)

Here we have to use the identity

(x + a)(x + b)(x + c) = x³ + (a + b + c)x² + (ab + bc + ca)x + abc

∴ – (5x + 2)(5x – 1)(5x + 3)

here x = 5x, a = 2, b = – 1 and c = 3

= – (5x)³ – (2 – 1 + 3)(5x)² – (– 2 – 3 + 6)5x + 6

= – 125x³ – 100x² – 5x + 6

Here coefficient of

x² = – 100

x = – 5 and

constant term = 6