Q. 34.1( 92 Votes )

# Check whether the

Answer :

Let us take A = {1, 2, 3, 4, 5, 6}

A relation R is defined on set A as:

R = {(a, b): b = a + 1}

Then, R = {(1,2), (2,3), (3,4), (4,5), (5,6)}

Now, we will find (a, a) R, where a ϵ A

For instance,

(1,1), (2,2), (3,3), (4,4), (5,5), (6,6) R

Therefore, R is not reflexive.

We can see that (1,2) ϵ R, but (2,1) R.

Therefore, R is not symmetric.

And now, (1,2), (2,3) ϵ R

But, (1,3) R

Therefore, R is not transitive.

Therefore, R is neither reflexive, nor symmetric, nor transitive.

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