(x – 2y – 4z)2Here the identity used is(x + y + z) 2 = x2 + y2 + z2 + 2xy + 2yz + 2zx∴ (x – 2y – 4z) 2= x2 + (– 2y)2 + (– 4z)2 + 2(x)(– 2y) + 2(– 2y)(– 4z) + 2 (– 4z)(x)= x2 + 4y2 + 16z2 – 4xy + 16yz – 8yz

Q. 1 C5.0( 2 Votes )

Expand the follow

Class 9th Tamilnadu Board Math Term-II 1. Algebra

Answer :

(x – 2y – 4z)²

Here the identity used is

(x + y + z) ² = x² + y² + z² + 2xy + 2yz + 2zx

∴ (x – 2y – 4z) ²

= x² + (– 2y)² + (– 4z)² + 2(x)(– 2y) + 2(– 2y)(– 4z) + 2 (– 4z)(x)

= x² + 4y² + 16z² – 4xy + 16yz – 8yz

Rate this question :

How useful is this solution?

We strive to provide quality solutions. Please rate us to serve you better.

PREVIOUSExpand the follow NEXTExpand the follow

Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts

Dedicated counsellor for each student

24X7 Doubt Resolution

Daily Report Card

Detailed Performance Evaluation

view all courses