(x – 2y – 4z)2
Here the identity used is
(x + y + z) 2 = x2 + y2 + z2 + 2xy + 2yz + 2zx
∴ (x – 2y – 4z) 2
= x2 + (– 2y)2 + (– 4z)2 + 2(x)(– 2y) + 2(– 2y)(– 4z) + 2 (– 4z)(x)
= x2 + 4y2 + 16z2 – 4xy + 16yz – 8yz
Rate this question :
How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
view all courses
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation