Answer :

It is given that relation R in the set A = {1, 2, 3, 4, 5, 6} as

R = {(x, y) : y is divisible by x}


We know that any number (x) is divisible by itself.


(x,x) ϵ R


R is reflexive.


Now, (2,4) ϵ R but (4,2) R.


R is not symmetric.


Let (x,y), (y,z) ϵ R. Then, y is divisible x and z is divisible by y.


z is divisible by x.


(x,z) ϵ R


R is transitive.


Therefore, R is reflexive and transitive but not symmetric.


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