Answer :

It is given that Relation R in the set A = {1, 2, 3, ..., 13, 14} defined as

R = {(x, y) : 3x – y = 0}


Then, R = {(1,3), (2,6), (3,9), (4,12)}

REFLEXIVE
A relation is said to be reflexive if (x, x)  ϵ  R, where x is from domain. 

R is not reflexive as (1,1), (2,2) …… (14,14) ∉ R


SYMMETRIC 
A relation is said to be symmetric if (y, x)  ϵ  R whenever (x, y) ϵ R.

Also, R is not symmetric as (1,3) ϵ R, but (3,1) ∉ R


TRANSITIVE

A relation is said to be transitive if (x, z)  ϵ  R whenever (x, y) ϵ R and (y, z) ϵ R
And, also R is not transitive as (1,3), (3,9) ϵ R, but (1,9) ∉ R


Therefore, R is neither reflexive, nor symmetric, nor transitive.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

Fill in theMathematics - Exemplar

State True Mathematics - Exemplar

State True Mathematics - Exemplar

State True Mathematics - Exemplar

Let A = {1, 2, 3}Mathematics - Exemplar

Show that the relMathematics - Board Papers

Let N denote the Mathematics - Board Papers