# L.C.M of two numbers is 14 times their H.C.F. The sum of L.C.M and H.C.F is 600.If one number is 280 find the other?

According to the given condition

L.C.M = 14 X, H.C.F + L.C.M = 600, 1 NUMBER= 280

Let the H.C.F (a,b) = X where a = 280 and b = ?

But H.C.F + L.C.M = 600

X + 14X = 600

15X = 600

X = 40

H.C.F = 40

L.C.M = 14 X

14 × 40= 560

Also H.C.F × L.C.M = 1ST NUMBER × 2ND NUMBER

40 × 560 = 280 × b

b = 40 × 2

b = 80

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