Q. 54.0( 4 Votes )

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Answer :

According to the given condition

L.C.M = 14 X, H.C.F + L.C.M = 600, 1 NUMBER= 280


Let the H.C.F (a,b) = X where a = 280 and b = ?


But H.C.F + L.C.M = 600


X + 14X = 600


15X = 600



X = 40


H.C.F = 40


L.C.M = 14 X


14 × 40= 560


Also H.C.F × L.C.M = 1ST NUMBER × 2ND NUMBER


40 × 560 = 280 × b



b = 40 × 2


b = 80


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