In a class of 60 A. 0

B. 25

C. 35

D. 45

Given:

Total number of students are 60

Students who play cricket and tennis are 25 and 20 respectively

Students who play both the games are 10

To find: number of students who play neither

Let S be the total number of students, C and T be the number of students who play cricket and tennis respectively

n(S) = 60, n(C) = 25, n(T) = 20, n(C ∩ T) = 10

Number of students who play either of them = n(C ∪ T)

= n(C) + n(T) – n(C ∩ T)

= 25 + 20 – 10

= 35

Number of student who play neither

= Total – n(C ∪ T)

= 60 – 35

= 25

Hence, there are 25 students who play neither cricket nor tennis.