Q. 294.4( 14 Votes )

Suppose A1</ A. 15

B. 3

C. 45

D. 35

Answer :

Given:


To find: value of n


Since elements are not repeating, number of elements in A1 A2 A3 ……… A30 is 30 × 5


But each element is used 10 times


So, 10 × S = 30 × 5


10 × S = 150


S = 15


Since elements are not repeating, number of elements in B1 B2 B3 ……… Bn is 3 × n


But each element is used 9 times


So, 9 × S = 3 × n


9 × S = 3n




n = 45


Hence, the value of n is 45

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

Let A = {a, b, c,RS Aggarwal - Mathematics

If A and B be twoRS Aggarwal - Mathematics

(i) If A <span laRS Aggarwal - Mathematics

Using propeMathematics - Exemplar

If A and B are twRS Aggarwal - Mathematics

In a town of 10,0RS Aggarwal - Mathematics

If A and B are twRS Aggarwal - Mathematics

If <a name="MTBlaRS Aggarwal - Mathematics

If n(A) = 3 and nRS Aggarwal - Mathematics

For any sets A, BRS Aggarwal - Mathematics