Q. 1955.0( 1 Vote )

The floor of a room is 8m 96cm long and 6m 72cm broad. Find the minimum number of square tiles of the same size needed to cover the entire floor.

Answer :

8m 96cm = 8 × 100 + 96 = 896 cm


6m 72cm = 6 × 100 + 72 = 672 cm


Side of largest square tile that can be used = HCF of 896 and 672 = 224 cm


Area of the tile = side × side = 224 × 224 cm2


Area of the floor = length × breadth = 896 × 672 cm2


Hence, Minimum number of tiles required = Area of floor/area of tile =



= 32 tiles


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