Q. 1894.0( 4 Votes )

Determine the least number which when divided by 3, 4 and 5 leaves remainder 2 in each case.

Answer :

Least number which when divided by 3, 4 and 5 leaves remainder 0 in each case = LCM of 3, 4 and 5


3 = 3 × 1


4 = 2 × 2


5 = 5 × 1


LCM = 3 × 2 × 2 × 5 = 60


Hence, the least number which when divided by 3, 4 and 5 leaves remainder 2 in each case = 60 + 2 = 62


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