Q. 1894.0( 4 Votes )
Determine the least number which when divided by 3, 4 and 5 leaves remainder 2 in each case.
Answer :
Least number which when divided by 3, 4 and 5 leaves remainder 0 in each case = LCM of 3, 4 and 5
3 = 3 × 1
4 = 2 × 2
5 = 5 × 1
LCM = 3 × 2 × 2 × 5 = 60
Hence, the least number which when divided by 3, 4 and 5 leaves remainder 2 in each case = 60 + 2 = 62
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