Q. 154.0( 2 Votes )

Write five situations for the following where brackets would be necessary.

(a) 7(8 – 3)

(b) (7 + 2) (10 – 3)

Answer :

(a) 7(8 – 3)


Here 7(8 – 3)


Multiply 7 by each number by opening brackets


= (7×8) – (7×3)


= 56 – 21


= 35


Also By BODMAS, solve the bracket first -


= 7(8 – 3)


= 7×5


= 35


(b) (7 + 2)(10 – 3)


Here,(7 + 2)(10 – 3)


By opening brackets


= 7(10 – 3) + 2(10 – 3)


= {(7×10) – (7×3)} + {(2×10 – 2×3)}


= {70 – 21} + {20 – 6}


= 49 + 14


= 63


Also by BODMAS, solve the brackets -


= (7 + 2) (10 – 3)


= 9 × 7


= 63


Also solving 1st bracket then opening 2nd bracket


= (7 + 2)(10 – 3)


= 9(10 – 3)


= (9 x 10) – (9 x 3)


= 90 – 27


= 63


Again, solving 2nd bracket then opening 1st bracket


= (7 + 2)(10 – 3)


= (7 + 2)7


= (7 x 7) + (2 x 7)


= 49 + 14


= 63


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