Q. 1344.3( 7 Votes )

A multistorey building has 25 floors above the ground level each of height 5m. It also has 3 floors in the basement each of height 5m. A lift in building moves at a rate of 1m/s. If a man starts from 50m above the ground, how long will it take him to reach at 2nd floor of basement?

Answer :

We have


Since, it is given that the man starts from 50 m from the ground.


Distance of the man from the ground = 50 m


There are about 3 floors in the basement.


The man has to reach the 2nd floor of the basement and it is given that, distance between floors is 5 m.


So, distance between ground and 1st floor of basement = 5 m


And distance between 1st floor and 2nd floor of basement = 5 m


Distance between ground and 2nd floor of basement = 5 + 5


Distance between ground and 2nd floor of basement = 10 m


Total distance between man and 2nd floor of the basement is given by,


Total distance = Distance between man and ground + Distance between ground and 2nd floor basement


Total distance = 50 + 10


Total distance = 60 m


But, the speed of lift = 1 m/s


We need to find the time taken by the lift to reach 60 m at speed, 1 m/s.


Since,




Time = 60 s


Thus, it takes 60 seconds or 1 minute to reach at 2nd floor of the basement.


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