Answer :

For (a) → **a × 1 = a**

So, we can match (a) with (vi).

For (b) → **1 = Multiplicative identity**

1 is multiplicative identity because any integer multiplied with 1 gives the same integer.

So, we can match (b) with (iii).

For (c) → **(-a) ÷ (-b) = a ÷ b**

As

⇒ …(i)

And …(ii)

Comparing equations (i) and (ii), we get

(-a) ÷ (-b) = a ÷ b

So, we can match (c) with (v).

For (d) → **a × (-1) = -a**

As a × (-1) = -a × 1 = -a

So, we can match (d) with (vii).

For (e) → **a × 0 = 0**

0 multiplied with any integer equals to 0.

So, we can match (e) with (viii).

For (f) → **(-a) ÷ b = a ÷ (-b)**

As …(i)

And

⇒ …(ii)

Comparing equations (i) and (ii), we get

(-a) ÷ b = a ÷ (-b)

So, we can match (f) with (iv).

For (g) → **0 = additive identity**

0 is additive identity because any integer added to 0 gives the same integer.

So, we can match (g) with (ii).

For (h) → **a ÷ (-a) = -1**

As

⇒

⇒ a ÷ (-a) = -1

So, we can match (h) with (ix).

For (I) → **-a = Additive inverse of a**

(-a) is additive inverse because integer a added with –a gives 0.

So, we can match (I) with (i).

Arranging it into table:

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