Q. 5

Electric charges are distributed in a small volume. The flux of the electric field through a spherical surface of radius 10 cm surrounding the total charge is 25 V m. The flux over a concentric sphere of radius 20 cm will be
A. 25 V m

B. 50 V m

C. 100 V m

D. 200 V m.

Answer :

Gauss’ law states that the electric flux through a closed surface is equal to 1/ϵ0 times the total charge enclosed by the surface.



Φ = electric flux

E = electric field

ds = area element

q = charge enclosed

0 = electric permittivity of vacuum

Hence, the flux depends on the charge enclosed.

In this case, even though the volume of the sphere enclosing the charge is increasing, the net charge enclosed inside it is remaining the same.

Hence, the electric field will remain the same = 25 V m. (Option a)

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Kirchoff's Law for VoltageFREE Class
All About Faraday's law55 mins
Few Applications of Gauss's law54 mins
Kirchoff's current & Voltage lawFREE Class
Kirchoff's Voltage Law41 mins
Questions based on Kirchoff's Law for Voltage67 mins
Ohm's Law - Full Concept in one Go59 mins
NCERT Important Questions of Gauss's Law43 mins
Interactive Quiz on Kirchoff's Law38 mins
Learn Raoult's Law56 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses