Q. 33.5( 2 Votes )

E° values of some redox couples are given below. On the basis of these values choose the correct option.

E° values: Br2/Br- = 1.09; Ag+ / Ag(s) = 0.80

Cu2+ /Cu(s) = + 0.34; I2(s) /I = + 0.54

A. Cu will reduce Br-

B. Cu will reduce Ag

C. Cu will reduce I-

D. Cu will reduce Br2

Answer :

Reducing agents should have the ability to undergo oxidation that implies the property to easily loose electrons. Consequently the coupling element should have a greater tendency to attract the donated electron. As I- and Br- already are reduced ions so they cannot further undergo reduction. Between Ag and Br we can find from electrochemical series that the reduction potential of Br2 is more as compared to Ag.

Thus Cu will reduce Br2 as follows:



Corresponding [potential for the developed cell is



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