Q. 25

E° for the given

Answer :


E° = 2.71 V


For the given reaction the Nernst equation is written as,

For the given conditions,

(i) Ecell > 2.71 V, the current flows from cathode to anode (conventional direction)

(ii) Ecell < 2.71 V, i.e. the external voltage is greater than the emf of the cell, the direction of the flow is from anode to cathode (direction is reversed)


(i) As the conductivity is linearly dependent on the square root of concentration the line on Λ v/s c1/2 suggests that A is a strong electrolyte.

When initially when the concentration is increases the conductivity drops rapidly but after certain point there are enough ions and no more addition of B will decrease the conductivity significantly, thus B is a weak electrolyte.

(ii) Extrapolation of values of Λm gives the maximum values of conductivity i.e. Λ°m for strong electrolytes at zero concentration. This cannot be found for Weak electrolytes as the relation is non-linear curvature which does not meet the conductivity.

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