Answer :

Mg(s) + Cu2+ (0.01 M) ––– Mg2+ (0.001 M) + Cu(s)


(i) less than 2.71V, current will flow from copper to magnesium


(ii) more than 2.71V, curret will from magnesium to copper


OR


a) (i)



2.8g of Fe requires = (2) (96500)(2.8)/(56)


= 9650 Coulombs


Q= It = (9650)(2) = 4825 sec


(ii)



(2) (96500) C of electricity deposit Zn = 65.3g


Therefore, 96500 C of electricity deposit Zn = (65.3) (96500)(9650) = 3.265g


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

<span lang="EN-USChemistry - Board Papers

Assertion : MercuChemistry - Exemplar

Note : In the folChemistry - Exemplar

What advantage doChemistry - Exemplar

E° cell forChemistry - Board Papers